Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321755936
ISBN 13: 978-0-32175-593-3

Chapter 3 - Probability - Exercises 3.112 - 3.137 - Applying the Concepts - Intermediate - Page 162: 3.127

Answer

Possible combinations for one group are 50C2 = 50! / 2! (50-2)! = 50 x 49 x 48! / 2! 48! = 50 x 49 / 2 = 1,225 Since there are two groups, so applying rule of multiplication 1,225 x 1,225 = 1,500,625

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