Essentials of Statistics (5th Edition)

Published by Pearson
ISBN 10: 0-32192-459-2
ISBN 13: 978-0-32192-459-9

Chapter 7 - Estimates and Sample Sizes - Review - Review Exercises - Page 367: 2

Answer

4144

Work Step by Step

$\alpha=1-0.99=0.01.$ Using the table: $z_{\alpha/2}=z_{0.005}=2.575.$ Hence the minimum sample size:$\frac{z_{\alpha/2}^2\cdot 0.25}{E^2}=\frac{2.575^2\cdot 0.25}{0.02^2}\approx4144$.
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