Answer
(a) 95%
(b) 38
(c) For \$90,500, z ≈ 4.67
For \$79,750, z = -2.5
For \$82,600, z = -0.6
The salaries of \$90,500 and \$79,750 are unusual.
Work Step by Step
Use empirical rule to estimate percentage
z = (x – μ) / σ
Values of z score between -2 and 2 are usual
