Answer
a) 0.108
b) 0.76
c) No, not unusual; probability $\gt 0.05$
Work Step by Step
Let the variables below represent:
A = Pregnancy
B = Multiple births
a)
Calculate the "and" probability as follows:
$P(A\times B)= P(A)\times P(B)= 0.45\times 0.24=0.108$
b)
Calculate the "not" probability as follows:
$P(B'\lvert A)= 1-P(B\lvert A)= 1-0.24=0.76$
c) No, it would not be unusual for a randomly selected embryo transfer to result in a pregnancy and produce a multiple birth because its probability is $0.108$, which is not less than $0.05$.
