Answer
$P(E)=\frac{1}{3}\approx0.333$
Work Step by Step
The sample space = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12} (12 outcomes)
Event E = {3, 6, 9, 12} (4 outcomes)
$P(E)=\frac{4}{12}=\frac{1}{3}\approx0.333$
Elementary Statistics: Picturing the World (6th Edition)
by Larson, Ron; Farber, Betsy
Published by
Pearson
ISBN 10:
0321911210
ISBN 13:
978-0-32191-121-6
Chapter 3 - Probability - Section 3.1 Basic Concepts of Probability and Counting - Exercises - Page 141: 33
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