Answer
(a) z = -0.22
(b) A towing capacity of 11,300 pounds is about 0.22 standard deviations below the mean.
(c) Not Unusual
Work Step by Step
z = (11300 - 11830)/2370 = -0.22
z score between -2 and 2 is usual
You need to log in to continue
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.