Answer
33
Work Step by Step
$\alpha=1-0.95=0.5.$ Using the table: $z_{\alpha/2}=z_{0.025}=1.96.$
Hence the sample size:$\left (\frac{z_{\alpha/2}\cdot \sigma}{E}\right)^2=\left (\frac{1.96\cdot 5.8}{2}\right)^2\approx33$.
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