Elementary Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321836960
ISBN 13: 978-0-32183-696-0

Chapter 7 - Estimates and Sample Sizes - Review - Chapter Quick Quiz - Page 373: 5

Answer

752

Work Step by Step

$\alpha=1-0.9=0.1.$ Then, by using the table, the critical value: $z_{\alpha/2}=z_{0.05}=1.645.$ $\hat{p}$ is unknown, hence:$n=\frac{z^2_{\frac{\alpha}{2}}\cdot0.25}{E^2}=\frac{1.645^2\cdot0.25}{0.03^2}=752.$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.