Answer
there is no difference.
Work Step by Step
The sample size is more than 25, hence the value of the test statistic: $z=\frac{(x+0.5)-n/2}{\sqrt n/2}=\frac{(14+0.5)-34/2}{\sqrt{34}/2}=-0.86.$ By using the table, the corresponding critical value: $z=\pm 1.96.$ If the value of the test statistic is in the rejection region, we reject the null hypothesis. -0.86 is between -1.96 and 1.96 hence we fail to reject the null hypothesis, hence there is no difference.
