Answer
There is a difference.
Work Step by Step
The sample size is more than 25, hence the value of the test statistic: $z=\frac{(x+0.5)-n/2}{\sqrt n/2}=\frac{(151+0.5)-1064/2}{\sqrt{1064}/2}=-23.33.$ By using the table, the corresponding critical value: $z=\pm 1.96.$ If the value of the test statistic is in the rejection region, we reject the null hypothesis. -23.33 is less than -1.96 hence we reject the null hypothesis, hence there is a difference.
