Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 8 - Polar Coordinates; Vectors - Section 8.7 The Cross Product - 8.7 Assess Your Understanding - Page 653: 65

Answer

$(17, 4.22),(-17, 1.08)$

Work Step by Step

1. Given $x=-8, y=-15$ (quadrant III), we have $r=\sqrt {64+225}=17$ and $\theta=tan^{-1}(\frac{-15}{-8})\approx4.22$. Thus we have $(17, 4.22)$ in polar coordinates. 2. For the same point, let $r=-17$, we have $\theta\approx4.22-\pi\approx1.08$, thus we have $(-17, 1.08)$ in polar coordinates for the same point.
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