Answer
$\sqrt 3$
Work Step by Step
Let $cos^{-1}(\frac{1}{2})=t$ (t in quadrant I), we have
$cos(t)=\frac{1}{2}$ and $sin(t)=\frac{\sqrt 3}{2}$,
thus $tan(t)=\sqrt 3$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 8 - Polar Coordinates; Vectors - Section 8.4 Vectors - 8.4 Assess Your Understanding - Page 630: 104
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