Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 8 - Polar Coordinates; Vectors - Section 8.2 Polar Equations and Graphs - 8.2 Assess Your Understanding - Page 605: 6

Answer

$ -\frac{1}{2}$

Work Step by Step

$cos\frac{2\pi}{3}=cos(\pi-\frac{\pi}{3})=-cos(\frac{\pi}{3})=-\frac{1}{2}$
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