Answer
$\frac{19}{15}$
Work Step by Step
$log_4(x+3)-log_4(x-1)=2$,
$log_4(\frac{x+3}{x-1})=2$,
$\frac{x+3}{x-1}=4^2=16$,
$x+3=16x-16$,
$15x=19$,
$x=\frac{19}{15}$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 8 - Polar Coordinates; Vectors - Section 8.1 Polar Cordinates - 8.1 Assess Your Understanding - Page 593: 88
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