Answer
$A$
Work Step by Step
Add $1$ revolution $(2\pi \text{ radians})$ to the angle we have to obtain:
$$-\frac{11\pi}{6}+2\pi=\frac{\pi}{6}$$
so the point $A$ has the polar coordinates $(2,-11\pi /6)$.
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 8 - Polar Coordinates; Vectors - Section 8.1 Polar Cordinates - 8.1 Assess Your Understanding - Page 591: 9
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