Answer
$6i-10j$
Work Step by Step
Let us consider two vectors $v_1=pi+qj$ and $v_2=xi+yj$; then we have: $v_1 +v_2 =(p + x)i+(q +y)j$
Therefore,
$v_1 +2v_2-v_3= (4i+6j) +2(-3i-6j)-(-8i+4j) \\
= 4i+6j -6i-12j+8i-4j \\
=6i-10j$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 8 - Polar Coordinates; Vectors - Chapter Test - Page 657: 19
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