Answer
$(4,\frac{\pi}{3})$
Work Step by Step
Given $(2,2\sqrt 3)$ (in quadrant I) in rectangular coordinates, use the transformation formulas, we have
$r=\sqrt {2^2+(2\sqrt 3)^2}=4$ and
$\theta=tan^{-1}(\frac{2\sqrt 3}{2})=\frac{\pi}{3}$,
thus $(4,\frac{\pi}{3})$ in polar coordinates.
