Answer
Amplitude, $A=|5|=5$ and period: $T=\dfrac{2\pi}{4}=\dfrac{\pi}{2}$
Work Step by Step
When the function has the form $y=A\sin{(\alpha x)}$, then $|A|$ denotes the amplitude and $T $ represents the period.
The period $T$ can be computed as: $T=\dfrac{2\pi}{\omega}$.
Here, we have:
Amplitude, $A=|5|=5$ and period: $T=\dfrac{2\pi}{4}=\dfrac{\pi}{2}$