Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 7 - Applications of Trigonometric Functions - Section 7.5 Simple Harmonic Motion; Damped Motion; Combining Waves - 7.5 Assess Your Understanding - Page 574: 1

Answer

Amplitude, $A=|5|=5$ and period: $T=\dfrac{2\pi}{4}=\dfrac{\pi}{2}$

Work Step by Step

When the function has the form $y=A\sin{(\alpha x)}$, then $|A|$ denotes the amplitude and $T $ represents the period. The period $T$ can be computed as: $T=\dfrac{2\pi}{\omega}$. Here, we have: Amplitude, $A=|5|=5$ and period: $T=\dfrac{2\pi}{4}=\dfrac{\pi}{2}$
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