Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 7 - Applications of Trigonometric Functions - Section 7.4 Area of a Triangle - 7.4 Assess Your Understanding - Page 565: 35

Answer

$\$5,446.38$

Work Step by Step

By Heron's formula, the area of a triangle with sides $a,b$ and $c$ is given by: $K=\sqrt{s(s-a)(s-b)(s-c)}$; where $s=\dfrac{a+b+c}{2}$ Therefore, $s=\dfrac{100+50+75}{2}=112.5$ and $K=\sqrt{112.5(112.5-100)(112.5-50)(112.5-75)}\approx 1815.46$ The unit price is $\$3$ per square foot. So, we will multiply the area and the cost per square foot to get the total cost. Thus, $\$3 \times (1815.46)=\$5,446.38$
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