Answer
See below.
Work Step by Step
$LHS=2cot\theta cot(2\theta)=\frac{2cot\theta}{tan(2\theta)}
=\frac{2cot\theta(1-tan^2\theta)}{2tan(\theta)}
=\frac{cot(\theta)-tan(\theta)}{tan(\theta)}
=cot^2\theta-1
=RHS$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 6 - Analytic Trigonometry - Chapter Review - Review Exercises - Page 527: 40
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