Answer
$y=\pm 4\sin(2\pi x)$
Work Step by Step
Amplitude=$|A|=4$
$\implies A=\pm4$
Period $T=\frac{2\pi}{\omega}=1\implies\omega=\frac{2\pi}{1}=2\pi$
Hence,
$y=A\sin(\omega x)=\pm 4\sin(2\pi x)$
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