Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 4 - Exponential and Logarithmic Functions - Section 4.4 Logarithmic Functions - 4.4 Assess Your Understanding - Page 321: 32

Answer

$\dfrac{2}{3}$

Work Step by Step

Note that $y=\log_a x \text{ is equivalent to } x= a^y$ Thus, if $y = \log_{5} \sqrt[3]{25}$, then $5^y=\sqrt[3]{25}$. Since $\sqrt[3]{25}=25^{\frac{1}{3}}=(5^2)^{\frac{1}{3}}=5^{\frac{2}{3}},$ then $5^y=5^{\frac{2}{3}}$ Use the rule $a^m=a^n \implies m=n$ to obtain: $y=\dfrac{2}{3}$ Therefore, $ \log_{5} \sqrt[3]{25} = \boxed{\dfrac{2}{3}}$
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