Answer
$ -8,-4,-\frac{7}{3}$.
Work Step by Step
Step 1. Use synthetic division or graphing to find zeros of $f(x)=3x^3+16x^2+3x-10$ as $x=-5,-1,\frac{2}{3}$, see graph.
Step 2. As $f(x+3)$ can be obtained by shifting $f(x)$ 3 units to the left, the zeros for $f(x+3)$ are $x=-8,-4,-\frac{7}{3}$.