Answer
(a) $x=-2,4$.
(b) $x=0,6$.
Work Step by Step
(a) Given $h(x)=(x+2)(x-4)^3$, we can identify the x-intercept(s) as $x=-2,4$.
(b) As $y=h(x-2)$ can be obtained from $y=h(x)$ by shifting the curve 2 units to the right, the new x-intercepts are $x=0,6$.
