Answer
$2\sqrt{10}$
Work Step by Step
Simplify the expression inside then apply the product rule for radicals to obtain:
$\sqrt{8^2-4.2.3}\\
=\sqrt{64-24}\\
=\sqrt{40}\\
=\sqrt{4(10)}\\
=\sqrt4\cdot \sqrt{10}\\
=2\sqrt{10}$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 2 - Linear and Quadratic Functions - Section 2.3 Quadratic Functions and Their Zeros - 2.3 Assess Your Understanding - Page 145: 2
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