Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 13 - A Preview of Calculus: The Limit, Derivative, and Integral of a Function - Section 13.3 One-sided Limits; Continuous Functions - 13.3 Assess Your Understanding - Page 908: 1

Answer

$f(0)=0$ and $f(2)=3$

Work Step by Step

$x=0$ lies in the interval $x\leq0$; therefore, $f(x)=x^2$ When $x=0$, then we have: $f(0)=0^2=0$ Since, $x=2$ lies in the interval $2\leq x\leq5$, therefore $f(x)=5-x$ When $x=2$, then we have: $f(2)=5-2=3$
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