Answer
$f(0)=0$ and $f(2)=3$
Work Step by Step
$x=0$ lies in the interval $x\leq0$; therefore, $f(x)=x^2$
When $x=0$, then we have: $f(0)=0^2=0$
Since, $x=2$ lies in the interval $2\leq x\leq5$, therefore $f(x)=5-x$
When $x=2$, then we have: $f(2)=5-2=3$