Answer
$2$
Work Step by Step
$\lim_{x\to3}(\frac{x^2-9}{x^2-3x})=\lim_{x\to3}(\frac{(x+3)(x-3)}{x(x-3)})=\lim_{x\to3}(\frac{x+3}{x})=\frac{3+3}{3}=2$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 13 - A Preview of Calculus: The Limit, Derivative, and Integral of a Function - Section 13.1 Finding Limits Using Tables and Graphs - 13.1 Assess Your Understanding - Page 896: 12
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