Chapter 12 - Counting and Probability - Section 12.3 Probability - 12.3 Assess Your Understanding - Page 886: 55

$0.936$ or $93.6\%$

We that $P(\text{an event happens})=1-P(\text{an event does not happen})$ Note that $6.4 \%=0.064$. Thus, using the formula above gives $P(\text{No money spent in gambling})=1-P(\text{Money spent in gambling})=1-0.064=0.936$ Hence, $P(\text{No money spent in gambling})=0.936=93.6\%$