Answer
$0.1$
Work Step by Step
The Addition Rule of Probabilities says that: $P(A\cup B)=P(A)+P(B)-P(A\cap B)$.
If A and B are mutually exclusive, then $P(A\cap B)=0$.
Solve for $P(A\cap B)$ in the formula above to obtain:
$P(A\cup B)=P(A)+P(B)-P(A\cap B)\\
P(A\cap B)=P(A)+P(B)-P(A\cup B)\\$
Substitute the given values then solve for $P(A\cap B)$ to obtain:
$P(A\cap B)=0.25+0.46-0.6=0.1$
