Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 12 - Counting and Probability - Section 12.3 Probability - 12.3 Assess Your Understanding - Page 884: 6

Answer

$\frac{1}{2}, \frac{3}{4},\frac{2}{3}, 0$.

Work Step by Step

By definition the probability of an event can be in the range of $[0,1]$, thus the possible probabilities are $\frac{1}{2}, \frac{3}{4},\frac{2}{3}, 0$.
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