Answer
$ \frac{\sqrt 6+\sqrt 2}{4}$
$ \frac{\sqrt 6+\sqrt 2}{4}$
Work Step by Step
$sin75^\circ=sin(45^\circ+30^\circ)=sin45^\circ cos30^\circ+cos45^\circ sin30^\circ=(\frac{\sqrt 2}{2})(\frac{\sqrt 3}{2})+(\frac{\sqrt 2}{2})(\frac{1}{2})=\frac{\sqrt 6+\sqrt 2}{4}$
$cos15^\circ=sin(45^\circ-30^\circ)=cos45^\circ cos30^\circ+sin45^\circ sin30^\circ=(\frac{\sqrt 2}{2})(\frac{\sqrt 3}{2})+(\frac{\sqrt 2}{2})(\frac{1}{2})=\frac{\sqrt 6+\sqrt 2}{4}$