Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 12 - Counting and Probability - Chapter Review - Review Exercises - Page 888: 21

Answer

(a) $ 381024$ (b) $1260$

Work Step by Step

(a) $N=\ _9C_4\cdot\ _9C_3\cdot\ _9C_2=381024$ (b) Use the formula of distinguishable permutations, we have $N=\frac{9!}{4!3!2!}=1260$
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