Answer
$\frac{x^2}{7}+\frac{y^2}{16}=1$
Work Step by Step
1. Based on the given conditions, we have the center $(0,0)$, a vertical major axis, $c=3, a=4$, and $b^2=a^2-c^2=7$
2. Thus we have the equation $\frac{x^2}{7}+\frac{y^2}{16}=1$
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