Answer
a) $P(x)=x$
b) $A(x)=\dfrac{x^2}{16}$
Work Step by Step
(a) The length of the side of the square is $r=\dfrac{x}{4}$
So, the perimeter will be the length of the wire:
$P(x)=4*side=4*\frac{x}{4}=x$
b) The length of the side of the square is $r=\dfrac{x}{4}$
So, the area is:
$A(x)=side^2=(\dfrac{x}{4})^2=\dfrac{x^2}{16}$