Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 1 - Functions and Their Graphs - Section 1.5 Graphing Techniques: Transformations - 1.5 Assess Your Understanding - Page 98: 35

Answer

(a) $x=-7$ and $x=1$; (b) $x=-3$ and $x=5$; (c) $x=-5$ and $x=3$; (d) $x=5$ and $x=-3$;

Work Step by Step

Given the x-intercepts $x=-5$ and $x=3$ of $y=f(x)$, we have: (a) For $y=f(x+2)$, shift the x-coordinates 2 units to the left, thus new x-intercepts $x=-7$ and $x=1$; (b) For $y=f(x-2)$, shift the x-coordinates 2 units to the right, thus new x-intercepts $x=-3$ and $x=5$; (c) For $y=4f(x)$, stretch vertically by a factor of 4, thus new x-intercepts $x=-5$ and $x=3$; (d) For $y=f(-x)$, reflect across the y-axis, thus new x-intercepts $x=5$ and $x=-3$;
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