Answer
$\frac{1}{2}-\frac{\sqrt 3}{2}i$
Work Step by Step
$(\frac{\sqrt 3}{2}-\frac{1}{2}i)^2=(\frac{\sqrt 3}{2})^2-2(\frac{\sqrt 3}{2})(\frac{1}{2}i)+(\frac{1}{2}i)^2=\frac{3}{4}-\frac{\sqrt 3}{2}i-\frac{1}{4}=\frac{1}{2}-\frac{\sqrt 3}{2}i$
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