Answer
$\{x|x\ge-1\}$
see graph.
Work Step by Step
$x(4x+3)\le(2x+1)^2$
$4x^2+3x\le 4x^2+4x+1$
thus $\{x|x\ge-1\}$
see graph.
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Appendix A - Review - A.10 Internal Notation; Solving Inequalities - A.10 Assess Your Understanding - Page A87: 79
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