Answer
see graph.
Work Step by Step
Given $y=-4sin(2x-\pi)=-4sin[2(x-\frac{\pi}{2})]$, we can find its amplitude as $4$, period as $p=\frac{2\pi}{2}=\pi$, and phase shift as $\frac{\pi}{2}$ to the right, see graph.
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 6 - The Circular Functions and Their Graphs - 6.4 Translations of the Graphs of the Sine and Cosine Functions - 6.4 Exercises - Page 614: 45
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