Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 6 - The Circular Functions and Their Graphs - 6.3 Graphs of the Sine and Cosine Functions - 6.3 Exercises - Page 602: 46

Answer

$y=-3\ cos(4x)$

Work Step by Step

As $f(0)\ne0$, use the form $y=a\ cos(bx)$. We can identify the period as $p=\frac{\pi}{2}$, thus $\frac{2\pi}{b}=\frac{\pi}{2}$ and $b=4$. We can find the amplitude as $3$, let $a=-3$ which is good for $f(0)=-3$. The answer is $y=-3\ cos(4x)$
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