Answer
$\sin{\dfrac{\pi}{3}} =\dfrac{\sqrt3}{2}$
Work Step by Step
$\frac{\pi}{3}=60^o$ is a special angle that intersects the unit circle at the point $(\frac{1}{2}, \frac{\sqrt3}{2})$.
Since $\sin{\theta}=y$, then
$\sin{\frac{\pi}{3}} =\frac{\sqrt3}{2}$