Answer
$20\ in$
Work Step by Step
Given the area $A=\frac{1}{2}r^2\theta=50\ in^2$ and $r=5\ in$, we have $\frac{1}{2}\times5^2\theta=50$ which gives $\theta=4\ rad$. Thus the arc length is $L=r\theta=5\times4=20\ in$
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