Answer
$43^o N$.
Work Step by Step
RECALL:
The length of the arc $(s)$ intercepted by the central angle $\theta$ in a circle of radius $r$ is given by the formula:
$s = r\theta$, where $\theta$ is in radian measure.
The radius of Earth is around $6400$ km., and the distance between the two cities (which is $s$) is 1100 km.
Use the formula above to obtain:
$s=r\theta
\\1100=6400 \cdot \theta
\\\dfrac{1100}{6400} = \theta
\\0.171875=\theta
\\0.171875 \cdot \dfrac{180^o}{\pi}=\theta
\\9.847712104^o=\theta
\\\theta \approx 10^o$
Since Charleston is found below Toronto on the map, then the latitude of Toronto must be 10 degrees higher than Charleston.
Thus, the latitude of Toronto must be:
$=33^o+10^o
\\=43^o N$.
