Answer
$145.6\ m$
Work Step by Step
Use the figure given in the exercise, assume the horizontal gap is $y$, we have $tan(14^\circ10')=\frac{28}{y}$ and $tan(46^\circ40')=\frac{x-28}{y}$, thus $\frac{28}{tan(14^\circ10')}=\frac{x-28}{tan(46^\circ40')}$ which gives $x=28+\frac{28tan(46^\circ40')}{tan(14^\circ10')}\approx145.6\ m$