Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - 5.4 Solutions and Applications off Right Triangles - 5.4 Exercises - Page 549: 50

Answer

$145.6\ m$

Work Step by Step

Use the figure given in the exercise, assume the horizontal gap is $y$, we have $tan(14^\circ10')=\frac{28}{y}$ and $tan(46^\circ40')=\frac{x-28}{y}$, thus $\frac{28}{tan(14^\circ10')}=\frac{x-28}{tan(46^\circ40')}$ which gives $x=28+\frac{28tan(46^\circ40')}{tan(14^\circ10')}\approx145.6\ m$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.