Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - 5.4 Solutions and Applications off Right Triangles - 5.4 Exercises - Page 546: 5

Answer

C

Work Step by Step

Recall: $\sin\theta=\frac{\text{side opposite}}{\text{hypotenuse}}$ Given: $x=5\sin 38^{\circ}$ $\implies \sin 38^{\circ}=\frac{x}{5}$ This implies that the opposite side to the $38^{\circ}$ angle is $x$ and the hypotenuse is the side with length $5$. This is the case in the right triangle C.
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