Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.9 - Linear Inequalities and Absolute Value Inequalities - Exercise Set - Page 140: 133

Answer

The given statement makes sense.

Work Step by Step

Consider the inequality as follows: $2x+3>5$ Now, put $x=0$ , Thus, $\begin{align} & 2\left( 0 \right)+3>5 \\ & 0+3>5 \\ & 3>5 \end{align}$ Which is a false statement. Had the inequality been satisfied, it would have been a true statement. Therefore, an inequality can be checked by substituting $x=0$
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