Answer
$(5,-3)$
Work Step by Step
The line passing containing the point $ P(a,b,c)$ and parallel to the normal vector $ n=\lt p,q,r\gt $ can be represented by the parametric equations as shown below:
$ x=a+pt; y=b+qt; z=c+qt $
Here, $ t \to $ Real number.
Therefore, $ x=(2)^2+1=5; y=5-(2)^3=-3$
So, point is: $(5,-3)$
