Answer
hyperbola.
Work Step by Step
Step 1. From the given equation, we have
$A=23, B=26\sqrt 3, C=-3$
Step 2. Evaluate
$B^2-4AC=(26\sqrt 3)^2-4(23)(-3)=2028+276=2304$
Step 3. As $B^2-4AC\gt0$, the equation represents a hyperbola.
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 9 - Section 9.4 - Rotation of Axes - Exercise Set - Page 1010: 35
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