Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Section 9.3 - The Parabola - Exercise Set - Page 999: 105

Answer

$(x')^2-(y')^2=2$

Work Step by Step

Using the formula $(A-B)(A+B)=A^2-B^2$ we can rewrite the original equation as $\frac{1}{2}((x')^2-(y')^2)=1$ or $(x')^2-(y')^2=2$
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