Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Section 9.3 - The Parabola - Exercise Set - Page 998: 72

Answer

The receiver must be placed at 1.125 feet from the base of the smaller dish.

Work Step by Step

As per the given statement , we have Depth: $y=2$ and Diameter = 6 feet. This implies that Radius: $2x=6 \implies x=3$ Now, consider $x^2=4py$ This implies that $(3)^2=(4p)(2) \implies p=1.125$ Hence, the receiver must be placed at 1.125 feet from the base of the smaller dish.
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