Answer
focus $(0,\frac{3}{2})$, directrix $y=-\frac{3}{2}$
see graph.
Work Step by Step
Step 1. Rewriting the equation as $x^2=6y$, we have $4p=6$ and $p=\frac{3}{2}$ with the parabola opening upwards and vertex at $(0,0)$.
Step 2. We can find the focus at $(0,\frac{3}{2})$ and directrix as $y=-\frac{3}{2}$
Step 3. We can graph the parabola as shown in the figure.
